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5033354410391 = 11996341957557
BaseRepresentation
bin100100100111110101101…
…0011010011100110010111
3122211011222010022201210012
41021033223103103212113
51124431302212113031
614412142513150435
71026435133400126
oct111175323234627
918734863281705
105033354410391
1116706a738878a
126935b825b41b
132a68493ac388
141358894d1abd
158ade0a99b2b
hex493eb4d3997

5033354410391 has 4 divisors (see below), whose sum is σ = 5033396487912. Its totient is φ = 5033312332872.

The previous prime is 5033354410351. The next prime is 5033354410421. The reversal of 5033354410391 is 1930144533305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5033354410391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5033354410351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20858816 + ... + 21098741.

It is an arithmetic number, because the mean of its divisors is an integer number (1258349121978).

Almost surely, 25033354410391 is an apocalyptic number.

5033354410391 is a deficient number, since it is larger than the sum of its proper divisors (42077521).

5033354410391 is a wasteful number, since it uses less digits than its factorization.

5033354410391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42077520.

The product of its (nonzero) digits is 291600, while the sum is 41.

Adding to 5033354410391 its reverse (1930144533305), we get a palindrome (6963498943696).

The spelling of 5033354410391 in words is "five trillion, thirty-three billion, three hundred fifty-four million, four hundred ten thousand, three hundred ninety-one".

Divisors: 1 119963 41957557 5033354410391