Base | Representation |
---|---|
bin | 100100101000001111110… |
… | …1111001111110110011101 |
3 | 122211021020102201011001211 |
4 | 1021100133233033312131 |
5 | 1124440102420302201 |
6 | 14412410101104421 |
7 | 1026466005144406 |
oct | 111203757176635 |
9 | 18737212634054 |
10 | 5034234150301 |
11 | 1671008a32364 |
12 | 6938029b8111 |
13 | 2a6959731135 |
14 | 1359302969ad |
15 | 8ae42e23651 |
hex | 4941fbcfd9d |
5034234150301 has 4 divisors (see below), whose sum is σ = 5038350450912. Its totient is φ = 5030117849692.
The previous prime is 5034234150269. The next prime is 5034234150367. The reversal of 5034234150301 is 1030514324305.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5034234150301 - 25 = 5034234150269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5034234151301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2058148471 + ... + 2058150916.
It is an arithmetic number, because the mean of its divisors is an integer number (1259587612728).
Almost surely, 25034234150301 is an apocalyptic number.
It is an amenable number.
5034234150301 is a deficient number, since it is larger than the sum of its proper divisors (4116300611).
5034234150301 is a wasteful number, since it uses less digits than its factorization.
5034234150301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4116300610.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5034234150301 its reverse (1030514324305), we get a palindrome (6064748474606).
The spelling of 5034234150301 in words is "five trillion, thirty-four billion, two hundred thirty-four million, one hundred fifty thousand, three hundred one".
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