Base | Representation |
---|---|
bin | 10110111001001011001101… |
… | …00010100111000011110011 |
3 | 20121020202011110102200012221 |
4 | 23130211212202213003303 |
5 | 23044310012144302311 |
6 | 255023134124101511 |
7 | 13414110156502333 |
oct | 1334454642470363 |
9 | 217222143380187 |
10 | 50343032025331 |
11 | 1504a3a6157991 |
12 | 5790997694897 |
13 | 221243481c466 |
14 | c608898990c3 |
15 | 5c48100c3671 |
hex | 2dc9668a70f3 |
50343032025331 has 4 divisors (see below), whose sum is σ = 50343277307992. Its totient is φ = 50342786742672.
The previous prime is 50343032025311. The next prime is 50343032025343. The reversal of 50343032025331 is 13352023034305.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50343032025331 - 215 = 50343031992563 is a prime.
It is a super-2 number, since 2×503430320253312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50343032025311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122333205 + ... + 122744038.
It is an arithmetic number, because the mean of its divisors is an integer number (12585819326998).
Almost surely, 250343032025331 is an apocalyptic number.
50343032025331 is a deficient number, since it is larger than the sum of its proper divisors (245282661).
50343032025331 is a wasteful number, since it uses less digits than its factorization.
50343032025331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245282660.
The product of its (nonzero) digits is 97200, while the sum is 34.
Adding to 50343032025331 its reverse (13352023034305), we get a palindrome (63695055059636).
The spelling of 50343032025331 in words is "fifty trillion, three hundred forty-three billion, thirty-two million, twenty-five thousand, three hundred thirty-one".
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