Base | Representation |
---|---|
bin | 100100101000010010001… |
… | …1110000001001110010111 |
3 | 122211021102222001112212011 |
4 | 1021100210132001032113 |
5 | 1124440233230120043 |
6 | 14412422014205051 |
7 | 1026500660604124 |
oct | 111204436011627 |
9 | 18737388045764 |
10 | 5034313520023 |
11 | 1671049812a77 |
12 | 6938254b3787 |
13 | 2a6970000678 |
14 | 13593aa3774b |
15 | 8ae49da059d |
hex | 49424781397 |
5034313520023 has 4 divisors (see below), whose sum is σ = 5119640867880. Its totient is φ = 4948986172168.
The previous prime is 5034313520003. The next prime is 5034313520051. The reversal of 5034313520023 is 3200253134305.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5034313520023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5034313520003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42663673840 + ... + 42663673957.
It is an arithmetic number, because the mean of its divisors is an integer number (1279910216970).
Almost surely, 25034313520023 is an apocalyptic number.
5034313520023 is a deficient number, since it is larger than the sum of its proper divisors (85327347857).
5034313520023 is an equidigital number, since it uses as much as digits as its factorization.
5034313520023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85327347856.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 5034313520023 its reverse (3200253134305), we get a palindrome (8234566654328).
The spelling of 5034313520023 in words is "five trillion, thirty-four billion, three hundred thirteen million, five hundred twenty thousand, twenty-three".
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