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5034332222151 = 31678110740717
BaseRepresentation
bin100100101000010010110…
…0101010111001011000111
3122211021111021020201100120
41021100211211113023013
51124440303022102101
614412423523113023
71026501305556231
oct111204545271307
918737437221316
105034332222151
111671059327181
1269382b812773
132a6973b4b10b
1413593d305251
158ae4b846b36
hex494259572c7

5034332222151 has 4 divisors (see below), whose sum is σ = 6712442962872. Its totient is φ = 3356221481432.

The previous prime is 5034332222131. The next prime is 5034332222167. The reversal of 5034332222151 is 1512222334305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5034332222151 - 25 = 5034332222119 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5034332222131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839055370356 + ... + 839055370361.

It is an arithmetic number, because the mean of its divisors is an integer number (1678110740718).

Almost surely, 25034332222151 is an apocalyptic number.

5034332222151 is a deficient number, since it is larger than the sum of its proper divisors (1678110740721).

5034332222151 is a wasteful number, since it uses less digits than its factorization.

5034332222151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1678110740720.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 5034332222151 its reverse (1512222334305), we get a palindrome (6546554556456).

The spelling of 5034332222151 in words is "five trillion, thirty-four billion, three hundred thirty-two million, two hundred twenty-two thousand, one hundred fifty-one".

Divisors: 1 3 1678110740717 5034332222151