Base | Representation |
---|---|
bin | 100100101000010011001… |
… | …0110011111100001011001 |
3 | 122211021112011111001100211 |
4 | 1021100212112133201121 |
5 | 1124440314321221101 |
6 | 14412425103131121 |
7 | 1026501523210120 |
oct | 111204626374131 |
9 | 18737464431324 |
10 | 5034345101401 |
11 | 1671065623590 |
12 | 693833ba3aa1 |
13 | 2a697670a385 |
14 | 135940cd8ab7 |
15 | 8ae4ca3cc51 |
hex | 4942659f859 |
5034345101401 has 32 divisors (see below), whose sum is σ = 6304656948480. Its totient is φ = 3905332531200.
The previous prime is 5034345101381. The next prime is 5034345101441. The reversal of 5034345101401 is 1041015434305.
It is a cyclic number.
It is not a de Polignac number, because 5034345101401 - 213 = 5034345093209 is a prime.
It is a super-3 number, since 3×50343451014013 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5034345101441) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 59878545 + ... + 59962561.
It is an arithmetic number, because the mean of its divisors is an integer number (197020529640).
Almost surely, 25034345101401 is an apocalyptic number.
It is an amenable number.
5034345101401 is a deficient number, since it is larger than the sum of its proper divisors (1270311847079).
5034345101401 is a wasteful number, since it uses less digits than its factorization.
5034345101401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87505.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 5034345101401 in words is "five trillion, thirty-four billion, three hundred forty-five million, one hundred one thousand, four hundred one".
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