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5034443143 = 18127814603
BaseRepresentation
bin1001011000001001…
…11000000110000111
3110222212012012200011
410230010320012013
540302304140033
62151321331051
7235521026542
oct45404700607
913885165604
105034443143
1121538a2714
12b86036a87
1362302b052
1435a8a9859
151e6eabccd
hex12c138187

5034443143 has 4 divisors (see below), whose sum is σ = 5062257928. Its totient is φ = 5006628360.

The previous prime is 5034443119. The next prime is 5034443171. The reversal of 5034443143 is 3413444305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5034443143 - 25 = 5034443111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5034444143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13907121 + ... + 13907482.

It is an arithmetic number, because the mean of its divisors is an integer number (1265564482).

Almost surely, 25034443143 is an apocalyptic number.

5034443143 is a deficient number, since it is larger than the sum of its proper divisors (27814785).

5034443143 is a wasteful number, since it uses less digits than its factorization.

5034443143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27814784.

The product of its (nonzero) digits is 34560, while the sum is 31.

The square root of 5034443143 is about 70953.8099258947. The cubic root of 5034443143 is about 1713.8934281119.

Adding to 5034443143 its reverse (3413444305), we get a palindrome (8447887448).

The spelling of 5034443143 in words is "five billion, thirty-four million, four hundred forty-three thousand, one hundred forty-three".

Divisors: 1 181 27814603 5034443143