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5034444153 = 31678148051
BaseRepresentation
bin1001011000001001…
…11000010101111001
3110222212012021001120
410230010320111321
540302304203103
62151321335453
7235521032514
oct45404702571
913885167046
105034444153
1121538a3452
12b86037589
1362302b64b
1435a8a9d7b
151e6eac253
hex12c138579

5034444153 has 4 divisors (see below), whose sum is σ = 6712592208. Its totient is φ = 3356296100.

The previous prime is 5034444143. The next prime is 5034444157. The reversal of 5034444153 is 3514444305.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5034444153 - 222 = 5030249849 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5034444157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839074023 + ... + 839074028.

It is an arithmetic number, because the mean of its divisors is an integer number (1678148052).

Almost surely, 25034444153 is an apocalyptic number.

It is an amenable number.

5034444153 is a deficient number, since it is larger than the sum of its proper divisors (1678148055).

5034444153 is a wasteful number, since it uses less digits than its factorization.

5034444153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1678148054.

The product of its (nonzero) digits is 57600, while the sum is 33.

The square root of 5034444153 is about 70953.8170432007. The cubic root of 5034444153 is about 1713.8935427246.

Adding to 5034444153 its reverse (3514444305), we get a palindrome (8548888458).

The spelling of 5034444153 in words is "five billion, thirty-four million, four hundred forty-four thousand, one hundred fifty-three".

Divisors: 1 3 1678148051 5034444153