Search a number
-
+
5035345534301 = 6138214266777
BaseRepresentation
bin100100101000110000111…
…1110110101110101011101
3122211101002212222022022012
41021101201332311311131
51124444341424044201
614413112242001005
71026535361563115
oct111214176656535
918741085868265
105035345534301
111671529312635
12693a73046165
132a6aa5a695c4
141359d7b1a045
158aeaa7a75bb
hex49461fb5d5d

5035345534301 has 4 divisors (see below), whose sum is σ = 5043559801692. Its totient is φ = 5027131266912.

The previous prime is 5035345534259. The next prime is 5035345534333. The reversal of 5035345534301 is 1034355435305.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 642443928676 + 4392901605625 = 801526^2 + 2095925^2 .

It is a cyclic number.

It is not a de Polignac number, because 5035345534301 - 210 = 5035345533277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5035345534001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4107132776 + ... + 4107134001.

It is an arithmetic number, because the mean of its divisors is an integer number (1260889950423).

Almost surely, 25035345534301 is an apocalyptic number.

It is an amenable number.

5035345534301 is a deficient number, since it is larger than the sum of its proper divisors (8214267391).

5035345534301 is an equidigital number, since it uses as much as digits as its factorization.

5035345534301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8214267390.

The product of its (nonzero) digits is 810000, while the sum is 41.

The spelling of 5035345534301 in words is "five trillion, thirty-five billion, three hundred forty-five million, five hundred thirty-four thousand, three hundred one".

Divisors: 1 613 8214266777 5035345534301