Base | Representation |
---|---|
bin | 100100101000110001001… |
… | …0100100000110110111111 |
3 | 122211101010021122221111212 |
4 | 1021101202110200312333 |
5 | 1124444344402344201 |
6 | 14413113003435035 |
7 | 1026535461064406 |
oct | 111214224406677 |
9 | 18741107587455 |
10 | 5035351215551 |
11 | 1671531542a88 |
12 | 693a74b25a7b |
13 | 2a6aa6ca84a7 |
14 | 1359d879863d |
15 | 8aeab02aabb |
hex | 49462520dbf |
5035351215551 has 4 divisors (see below), whose sum is σ = 5300369700600. Its totient is φ = 4770332730504.
The previous prime is 5035351215529. The next prime is 5035351215571. The reversal of 5035351215551 is 1555121535305.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5035351215551 - 210 = 5035351214527 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5035351215499 and 5035351215508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5035351215571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132509242496 + ... + 132509242533.
It is an arithmetic number, because the mean of its divisors is an integer number (1325092425150).
Almost surely, 25035351215551 is an apocalyptic number.
5035351215551 is a deficient number, since it is larger than the sum of its proper divisors (265018485049).
5035351215551 is a wasteful number, since it uses less digits than its factorization.
5035351215551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 265018485048.
The product of its (nonzero) digits is 281250, while the sum is 41.
The spelling of 5035351215551 in words is "five trillion, thirty-five billion, three hundred fifty-one million, two hundred fifteen thousand, five hundred fifty-one".
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