Base | Representation |
---|---|
bin | 100100101000110011010… |
… | …1011110110010001100001 |
3 | 122211101022101110012112212 |
4 | 1021101212223312101201 |
5 | 1130000022124111231 |
6 | 14413124141131505 |
7 | 1026540340355102 |
oct | 111214653662141 |
9 | 18741271405485 |
10 | 5035424441441 |
11 | 1671569907749 |
12 | 693a95559b95 |
13 | 2a6ab9206414 |
14 | 135a043ba3a9 |
15 | 8aeb269242b |
hex | 49466af6461 |
5035424441441 has 32 divisors (see below), whose sum is σ = 5221269504000. Its totient is φ = 4853209878720.
The previous prime is 5035424441429. The next prime is 5035424441473. The reversal of 5035424441441 is 1441444245305.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5035424441441 is a prime.
It is a super-2 number, since 2×50354244414412 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5035424441491) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1085452400 + ... + 1085457038.
It is an arithmetic number, because the mean of its divisors is an integer number (163164672000).
Almost surely, 25035424441441 is an apocalyptic number.
It is an amenable number.
5035424441441 is a deficient number, since it is larger than the sum of its proper divisors (185845062559).
5035424441441 is a wasteful number, since it uses less digits than its factorization.
5035424441441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5909.
The product of its (nonzero) digits is 614400, while the sum is 41.
Adding to 5035424441441 its reverse (1441444245305), we get a palindrome (6476868686746).
The spelling of 5035424441441 in words is "five trillion, thirty-five billion, four hundred twenty-four million, four hundred forty-one thousand, four hundred forty-one".
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