Base | Representation |
---|---|
bin | 100100101000110011101… |
… | …0000110110001010110111 |
3 | 122211101100001200221221110 |
4 | 1021101213100312022313 |
5 | 1130000032114442333 |
6 | 14413125125050103 |
7 | 1026540515661555 |
oct | 111214720661267 |
9 | 18741301627843 |
10 | 5035434140343 |
11 | 1671574331672 |
12 | 693a98856933 |
13 | 2a6abb220c09 |
14 | 135a057c2bd5 |
15 | 8aeb345b063 |
hex | 494674362b7 |
5035434140343 has 8 divisors (see below), whose sum is σ = 6715494554368. Its totient is φ = 3356164909944.
The previous prime is 5035434140323. The next prime is 5035434140351. The reversal of 5035434140343 is 3430414345305.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5035434140343 - 29 = 5035434139831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5035434140323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 197781055 + ... + 197806512.
It is an arithmetic number, because the mean of its divisors is an integer number (839436819296).
Almost surely, 25035434140343 is an apocalyptic number.
5035434140343 is a deficient number, since it is larger than the sum of its proper divisors (1680060414025).
5035434140343 is a wasteful number, since it uses less digits than its factorization.
5035434140343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 395591813.
The product of its (nonzero) digits is 518400, while the sum is 39.
Adding to 5035434140343 its reverse (3430414345305), we get a palindrome (8465848485648).
The spelling of 5035434140343 in words is "five trillion, thirty-five billion, four hundred thirty-four million, one hundred forty thousand, three hundred forty-three".
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