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5036043400041 = 330710915011931
BaseRepresentation
bin100100101001000101110…
…0100111111001101101001
3122211102220112010120010110
41021102023210333031221
51130002304102300131
614413305411404533
71026561564415113
oct111221344771551
918742815116113
105036043400041
111671857234485
126940288b3749
132a6b8750c404
14135a6269a3b3
158aeebba7646
hex4948b93f369

5036043400041 has 16 divisors (see below), whose sum is σ = 6742772644608. Its totient is φ = 3343358264400.

The previous prime is 5036043400007. The next prime is 5036043400057. The reversal of 5036043400041 is 1400043406305.

It is not a de Polignac number, because 5036043400041 - 27 = 5036043399913 is a prime.

It is a super-3 number, since 3×50360434000413 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5036043399981 and 5036043400008.

It is not an unprimeable number, because it can be changed into a prime (5036043400081) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1501155 + ... + 3510776.

It is an arithmetic number, because the mean of its divisors is an integer number (421423290288).

Almost surely, 25036043400041 is an apocalyptic number.

It is an amenable number.

5036043400041 is a deficient number, since it is larger than the sum of its proper divisors (1706729244567).

5036043400041 is a wasteful number, since it uses less digits than its factorization.

5036043400041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5013332.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 5036043400041 its reverse (1400043406305), we get a palindrome (6436086806346).

The spelling of 5036043400041 in words is "five trillion, thirty-six billion, forty-three million, four hundred thousand, forty-one".

Divisors: 1 3 307 921 1091 3273 334937 1004811 5011931 15035793 1538662817 4615988451 5468016721 16404050163 1678681133347 5036043400041