Base | Representation |
---|---|
bin | 10110111001111100001100… |
… | …10111100100011000001111 |
3 | 20121100021001121122011010121 |
4 | 23130332012113210120033 |
5 | 23100222344431233310 |
6 | 255043204201245411 |
7 | 13416031045110052 |
oct | 1334760627443017 |
9 | 217307047564117 |
10 | 50369335805455 |
11 | 1505a573a33247 |
12 | 5795ab8793867 |
13 | 2214a671b53b4 |
14 | c61c63068a99 |
15 | 5c534e4810da |
hex | 2dcf865e460f |
50369335805455 has 4 divisors (see below), whose sum is σ = 60443202966552. Its totient is φ = 40295468644360.
The previous prime is 50369335805429. The next prime is 50369335805461. The reversal of 50369335805455 is 55450853396305.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 50369335805455 - 29 = 50369335804943 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50369335805393 and 50369335805402.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5036933580541 + ... + 5036933580550.
It is an arithmetic number, because the mean of its divisors is an integer number (15110800741638).
Almost surely, 250369335805455 is an apocalyptic number.
50369335805455 is a deficient number, since it is larger than the sum of its proper divisors (10073867161097).
50369335805455 is a wasteful number, since it uses less digits than its factorization.
50369335805455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10073867161096.
The product of its (nonzero) digits is 145800000, while the sum is 61.
The spelling of 50369335805455 in words is "fifty trillion, three hundred sixty-nine billion, three hundred thirty-five million, eight hundred five thousand, four hundred fifty-five".
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