Base | Representation |
---|---|
bin | 101110111011100100… |
… | …010100010100110011 |
3 | 11211001212111102202221 |
4 | 232323210110110303 |
5 | 1311200211000313 |
6 | 35052144421511 |
7 | 3432514453261 |
oct | 567344242463 |
9 | 154055442687 |
10 | 50391500083 |
11 | 1a409762941 |
12 | 9924017897 |
13 | 49a0bc6492 |
14 | 2620721431 |
15 | 149de29c8d |
hex | bbb914533 |
50391500083 has 4 divisors (see below), whose sum is σ = 50401837440. Its totient is φ = 50381162728.
The previous prime is 50391500077. The next prime is 50391500099. The reversal of 50391500083 is 38000519305.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50391500083 - 217 = 50391369011 is a prime.
It is a super-2 number, since 2×503915000832 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50391500053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5161363 + ... + 5171116.
It is an arithmetic number, because the mean of its divisors is an integer number (12600459360).
Almost surely, 250391500083 is an apocalyptic number.
50391500083 is a deficient number, since it is larger than the sum of its proper divisors (10337357).
50391500083 is a wasteful number, since it uses less digits than its factorization.
50391500083 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10337356.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 50391500083 in words is "fifty billion, three hundred ninety-one million, five hundred thousand, eighty-three".
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