Search a number
-
+
5040100131 = 311473249581
BaseRepresentation
bin1001011000110100…
…11101001100100011
3111000020211121121020
410230122131030203
540310231201011
62152042500523
7235620100323
oct45432351443
914006747536
105040100131
112157006910
12b87b04743
1362425bb91
1435b53d283
151e7728006
hex12c69d323

5040100131 has 16 divisors (see below), whose sum is σ = 7487036928. Its totient is φ = 2989613600.

The previous prime is 5040100127. The next prime is 5040100139. The reversal of 5040100131 is 1310010405.

It is not a de Polignac number, because 5040100131 - 22 = 5040100127 is a prime.

It is a super-2 number, since 2×50401001312 = 50805218661012434322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5040100131.

It is not an unprimeable number, because it can be changed into a prime (5040100139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1623240 + ... + 1626341.

It is an arithmetic number, because the mean of its divisors is an integer number (467939808).

Almost surely, 25040100131 is an apocalyptic number.

5040100131 is a deficient number, since it is larger than the sum of its proper divisors (2446936797).

5040100131 is a wasteful number, since it uses less digits than its factorization.

5040100131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3249642.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 5040100131 is about 70993.6626115317. The cubic root of 5040100131 is about 1714.5351306851.

Adding to 5040100131 its reverse (1310010405), we get a palindrome (6350110536).

The spelling of 5040100131 in words is "five billion, forty million, one hundred thousand, one hundred thirty-one".

Divisors: 1 3 11 33 47 141 517 1551 3249581 9748743 35745391 107236173 152730307 458190921 1680033377 5040100131