Base | Representation |
---|---|
bin | 100100101011000110001… |
… | …1010111100110100101001 |
3 | 122211212000211111012021121 |
4 | 1021112030122330310221 |
5 | 1130040120220411241 |
6 | 14415301142535241 |
7 | 1030103430315436 |
oct | 111261432746451 |
9 | 18755024435247 |
10 | 5040352513321 |
11 | 1673668657024 |
12 | 694a2ba37521 |
13 | 2a73c319c998 |
14 | 135d50ab6b8d |
15 | 8b1a013bad1 |
hex | 4958c6bcd29 |
5040352513321 has 4 divisors (see below), whose sum is σ = 5336843837652. Its totient is φ = 4743861188992.
The previous prime is 5040352513303. The next prime is 5040352513337. The reversal of 5040352513321 is 1233152530405.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1461971174400 + 3578381338921 = 1209120^2 + 1891661^2 .
It is not a de Polignac number, because 5040352513321 - 213 = 5040352505129 is a prime.
It is a super-3 number, since 3×50403525133213 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5040352513421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148245662140 + ... + 148245662173.
It is an arithmetic number, because the mean of its divisors is an integer number (1334210959413).
Almost surely, 25040352513321 is an apocalyptic number.
It is an amenable number.
5040352513321 is a deficient number, since it is larger than the sum of its proper divisors (296491324331).
5040352513321 is a wasteful number, since it uses less digits than its factorization.
5040352513321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 296491324330.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 5040352513321 in words is "five trillion, forty billion, three hundred fifty-two million, five hundred thirteen thousand, three hundred twenty-one".
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