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5040425413433 = 29180499629773
BaseRepresentation
bin100100101011001000011…
…0001000010101100111001
3122211212012220122220102202
41021112100301002230321
51130040242401212213
614415312305235545
71030105304051264
oct111262061025471
918755186586382
105040425413433
1116736a5818a53
12694a50332bb5
132a7405315547
14135d5a651cdb
158b1a673bb58
hex49590c42b39

5040425413433 has 8 divisors (see below), whose sum is σ = 5214522621000. Its totient is φ = 4866347501568.

The previous prime is 5040425413427. The next prime is 5040425413451. The reversal of 5040425413433 is 3343145240405.

It can be written as a sum of positive squares in 4 ways, for example, as 1226341404409 + 3814084009024 = 1107403^2 + 1952968^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5040425413433 - 26 = 5040425413369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5040425413403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4291466 + ... + 5338307.

It is an arithmetic number, because the mean of its divisors is an integer number (651815327625).

Almost surely, 25040425413433 is an apocalyptic number.

It is an amenable number.

5040425413433 is a deficient number, since it is larger than the sum of its proper divisors (174097207567).

5040425413433 is a wasteful number, since it uses less digits than its factorization.

5040425413433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9647851.

The product of its (nonzero) digits is 345600, while the sum is 38.

The spelling of 5040425413433 in words is "five trillion, forty billion, four hundred twenty-five million, four hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 29 18049 523421 9629773 279263417 173807772877 5040425413433