50412131101 has 4 divisors (see below), whose sum is σ = 52603962912. Its totient is φ = 48220299292.

The previous prime is 50412131017. The next prime is 50412131117. The reversal of 50412131101 is 10113121405.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50412131101 - 2¹³ = 50412122909 is a prime.

It is a super-2 number, since 2×50412131101² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50412131131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1095915871 + ... + 1095915916.

It is an arithmetic number, because the mean of its divisors is an integer number (13150990728).

Almost surely, 2^50412131101 is an apocalyptic number.

It is an amenable number.

50412131101 is a deficient number, since it is larger than the sum of its proper divisors (2191831811).

50412131101 is a wasteful number, since it uses less digits than its factorization.

50412131101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2191831810.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 50412131101 its reverse (10113121405), we get a palindrome (60525252506).

The spelling of 50412131101 in words is "fifty billion, four hundred twelve million, one hundred thirty-one thousand, one hundred one".