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5042113 = 47107279
BaseRepresentation
bin10011001110111111000001
3100111011110221
4103032333001
52242321423
6300023041
760600016
oct23167701
910434427
105042113
11293423a
121831a81
131076ccb
1495370d
15698e5d
hex4cefc1

5042113 has 4 divisors (see below), whose sum is σ = 5149440. Its totient is φ = 4934788.

The previous prime is 5042111. The next prime is 5042131. The reversal of 5042113 is 3112405.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112405 = 5622481.

It is a cyclic number.

It is not a de Polignac number, because 5042113 - 21 = 5042111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5042111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53593 + ... + 53686.

It is an arithmetic number, because the mean of its divisors is an integer number (1287360).

Almost surely, 25042113 is an apocalyptic number.

It is an amenable number.

5042113 is a deficient number, since it is larger than the sum of its proper divisors (107327).

5042113 is a wasteful number, since it uses less digits than its factorization.

5042113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107326.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 5042113 is about 2245.4649852536. The cubic root of 5042113 is about 171.4763345416.

Adding to 5042113 its reverse (3112405), we get a palindrome (8154518).

The spelling of 5042113 in words is "five million, forty-two thousand, one hundred thirteen".

Divisors: 1 47 107279 5042113