Base | Representation |
---|---|
bin | 100100101100000011100… |
… | …1000101001010011010111 |
3 | 122212001100022111000121020 |
4 | 1021120013020221103113 |
5 | 1130103324243443333 |
6 | 14420241330052223 |
7 | 1030205436653106 |
oct | 111300710512327 |
9 | 18761308430536 |
10 | 5042411312343 |
11 | 1674524804219 |
12 | 69530541a073 |
13 | 2a7660893462 |
14 | 1360a82ba03d |
15 | 8b270c663b3 |
hex | 496072294d7 |
5042411312343 has 8 divisors (see below), whose sum is σ = 6724616064000. Its totient is φ = 3360907051128.
The previous prime is 5042411312291. The next prime is 5042411312371. The reversal of 5042411312343 is 3432131142405.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5042411312343 - 217 = 5042411181271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5042411316343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175105813 + ... + 175134606.
It is an arithmetic number, because the mean of its divisors is an integer number (840577008000).
Almost surely, 25042411312343 is an apocalyptic number.
5042411312343 is a deficient number, since it is larger than the sum of its proper divisors (1682204751657).
5042411312343 is a wasteful number, since it uses less digits than its factorization.
5042411312343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 350245221.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 5042411312343 its reverse (3432131142405), we get a palindrome (8474542454748).
The spelling of 5042411312343 in words is "five trillion, forty-two billion, four hundred eleven million, three hundred twelve thousand, three hundred forty-three".
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