Base | Representation |
---|---|
bin | 100100101100011011101… |
… | …1111010100000011110011 |
3 | 122212010102211222201120012 |
4 | 1021120313133110003303 |
5 | 1130112004433423021 |
6 | 14420454030005135 |
7 | 1030234520316425 |
oct | 111306737240363 |
9 | 18763384881505 |
10 | 5043222561011 |
11 | 1674900728368 |
12 | 6954b10467ab |
13 | 2a775c98435b |
14 | 136143d32815 |
15 | 8b2bc0b135b |
hex | 496377d40f3 |
5043222561011 has 4 divisors (see below), whose sum is σ = 5308655327400. Its totient is φ = 4777789794624.
The previous prime is 5043222560993. The next prime is 5043222561019. The reversal of 5043222561011 is 1101652223405.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5043222561011 - 238 = 4768344654067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5043222561019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132716383166 + ... + 132716383203.
It is an arithmetic number, because the mean of its divisors is an integer number (1327163831850).
Almost surely, 25043222561011 is an apocalyptic number.
5043222561011 is a deficient number, since it is larger than the sum of its proper divisors (265432766389).
5043222561011 is a wasteful number, since it uses less digits than its factorization.
5043222561011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265432766388.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 5043222561011 its reverse (1101652223405), we get a palindrome (6144874784416).
The spelling of 5043222561011 in words is "five trillion, forty-three billion, two hundred twenty-two million, five hundred sixty-one thousand, eleven".
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