Base | Representation |
---|---|
bin | 1001011001001101… |
… | …10010000000100001 |
3 | 111000110220202122221 |
4 | 10230212302000201 |
5 | 40312043043410 |
6 | 2152240031041 |
7 | 235656415141 |
oct | 45446620041 |
9 | 14013822587 |
10 | 5043331105 |
11 | 215891333a |
12 | b89002481 |
13 | 624b206b7 |
14 | 35bb40921 |
15 | 1e7b654da |
hex | 12c9b2021 |
5043331105 has 4 divisors (see below), whose sum is σ = 6051997332. Its totient is φ = 4034664880.
The previous prime is 5043331103. The next prime is 5043331171. The reversal of 5043331105 is 5011333405.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1095345216 + 3947985889 = 33096^2 + 62833^2 .
It is not a de Polignac number, because 5043331105 - 21 = 5043331103 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5043331105.
It is not an unprimeable number, because it can be changed into a prime (5043331103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504333106 + ... + 504333115.
It is an arithmetic number, because the mean of its divisors is an integer number (1512999333).
Almost surely, 25043331105 is an apocalyptic number.
It is an amenable number.
5043331105 is a deficient number, since it is larger than the sum of its proper divisors (1008666227).
5043331105 is a wasteful number, since it uses less digits than its factorization.
5043331105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1008666226.
The product of its (nonzero) digits is 2700, while the sum is 25.
The square root of 5043331105 is about 71016.4143349972. The cubic root of 5043331105 is about 1714.9014220270.
The spelling of 5043331105 in words is "five billion, forty-three million, three hundred thirty-one thousand, one hundred five".
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