Base | Representation |
---|---|
bin | 10110111100000000001110… |
… | …00000101011010101101011 |
3 | 20121121001000012121020112102 |
4 | 23132000013000223111223 |
5 | 23102403024131323001 |
6 | 255135525245204015 |
7 | 13424120340662111 |
oct | 1336000700532553 |
9 | 217531005536472 |
10 | 50440213542251 |
11 | 15087635630a25 |
12 | 57a779956060b |
13 | 221b65142cb20 |
14 | c65468483ab1 |
15 | 5c70ebb71e6b |
hex | 2de00702b56b |
50440213542251 has 4 divisors (see below), whose sum is σ = 54320229968592. Its totient is φ = 46560197115912.
The previous prime is 50440213542239. The next prime is 50440213542281. The reversal of 50440213542251 is 15224531204405.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50440213542251 - 222 = 50440209347947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50440213542281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1940008213151 + ... + 1940008213176.
It is an arithmetic number, because the mean of its divisors is an integer number (13580057492148).
Almost surely, 250440213542251 is an apocalyptic number.
50440213542251 is a deficient number, since it is larger than the sum of its proper divisors (3880016426341).
50440213542251 is a wasteful number, since it uses less digits than its factorization.
50440213542251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3880016426340.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 50440213542251 its reverse (15224531204405), we get a palindrome (65664744746656).
The spelling of 50440213542251 in words is "fifty trillion, four hundred forty billion, two hundred thirteen million, five hundred forty-two thousand, two hundred fifty-one".
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