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50442351113551 = 120142000292351
BaseRepresentation
bin10110111100000100001100…
…11010110111010101001111
320121121020112011211010002211
423132002012122313111033
523102421413341113201
6255140521324531251
713424224325020315
oct1336020632672517
9217536464733084
1050442351113551
11150885321a0981
1257a80953b0b27
13221b902243c07
14c655cc3100b5
155c71c465b651
hex2de0866b754f

50442351113551 has 4 divisors (see below), whose sum is σ = 50484351407104. Its totient is φ = 50400350820000.

The previous prime is 50442351113549. The next prime is 50442351113591. The reversal of 50442351113551 is 15531115324405.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50442351113551 - 21 = 50442351113549 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50442351113591) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21000144975 + ... + 21000147376.

It is an arithmetic number, because the mean of its divisors is an integer number (12621087851776).

Almost surely, 250442351113551 is an apocalyptic number.

50442351113551 is a deficient number, since it is larger than the sum of its proper divisors (42000293553).

50442351113551 is a wasteful number, since it uses less digits than its factorization.

50442351113551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42000293552.

The product of its (nonzero) digits is 180000, while the sum is 40.

Adding to 50442351113551 its reverse (15531115324405), we get a palindrome (65973466437956).

The spelling of 50442351113551 in words is "fifty trillion, four hundred forty-two billion, three hundred fifty-one million, one hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 1201 42000292351 50442351113551