Base | Representation |
---|---|
bin | 1001011001110110… |
… | …00101100111111111 |
3 | 111000211221012202121 |
4 | 10230323011213333 |
5 | 40314423414320 |
6 | 2152550103411 |
7 | 236052565564 |
oct | 45473054777 |
9 | 14024835677 |
10 | 5048654335 |
11 | 21609197aa |
12 | b8a94ab67 |
13 | 625c6563a |
14 | 35c72886b |
15 | 1e83678aa |
hex | 12cec59ff |
5048654335 has 4 divisors (see below), whose sum is σ = 6058385208. Its totient is φ = 4038923464.
The previous prime is 5048654309. The next prime is 5048654419. The reversal of 5048654335 is 5334568405.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5048654335 - 27 = 5048654207 is a prime.
It is a super-3 number, since 3×50486543353 (a number of 30 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5048654291 and 5048654300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504865429 + ... + 504865438.
It is an arithmetic number, because the mean of its divisors is an integer number (1514596302).
Almost surely, 25048654335 is an apocalyptic number.
5048654335 is a deficient number, since it is larger than the sum of its proper divisors (1009730873).
5048654335 is a wasteful number, since it uses less digits than its factorization.
5048654335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1009730872.
The product of its (nonzero) digits is 864000, while the sum is 43.
The square root of 5048654335 is about 71053.8833210402. The cubic root of 5048654335 is about 1715.5045686756.
The spelling of 5048654335 in words is "five billion, forty-eight million, six hundred fifty-four thousand, three hundred thirty-five".
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