Base | Representation |
---|---|
bin | 100100110000001101000… |
… | …1110000011011110111111 |
3 | 122212220100021102222221221 |
4 | 1021200122032003132333 |
5 | 1130230101241310444 |
6 | 14424313420534211 |
7 | 1030642311510253 |
oct | 111403216033677 |
9 | 18786307388857 |
10 | 5051321431999 |
11 | 1678287295a77 |
12 | 696b913b1367 |
13 | 2a84508340cb |
14 | 1366b17b6263 |
15 | 8b5e30dba84 |
hex | 4981a3837bf |
5051321431999 has 4 divisors (see below), whose sum is σ = 5057459125936. Its totient is φ = 5045183738064.
The previous prime is 5051321431997. The next prime is 5051321432021. The reversal of 5051321431999 is 9991341231505.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5051321431999 - 21 = 5051321431997 is a prime.
It is a super-2 number, since 2×50513214319992 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5051321431993) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3068845734 + ... + 3068847379.
It is an arithmetic number, because the mean of its divisors is an integer number (1264364781484).
Almost surely, 25051321431999 is an apocalyptic number.
5051321431999 is a deficient number, since it is larger than the sum of its proper divisors (6137693937).
5051321431999 is an equidigital number, since it uses as much as digits as its factorization.
5051321431999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6137693936.
The product of its (nonzero) digits is 1312200, while the sum is 52.
The spelling of 5051321431999 in words is "five trillion, fifty-one billion, three hundred twenty-one million, four hundred thirty-one thousand, nine hundred ninety-nine".
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