Base | Representation |
---|---|
bin | 100100110000001101011… |
… | …0010100110011110111101 |
3 | 122212220100221110201222211 |
4 | 1021200122302212132331 |
5 | 1130230111214400131 |
6 | 14424314402140421 |
7 | 1030642456112002 |
oct | 111403262463675 |
9 | 18786327421884 |
10 | 5051331012541 |
11 | 1678291739a80 |
12 | 696b94651711 |
13 | 2a8452809a78 |
14 | 1366b2b8b8a9 |
15 | 8b5e3d805b1 |
hex | 4981aca67bd |
5051331012541 has 4 divisors (see below), whose sum is σ = 5510542922784. Its totient is φ = 4592119102300.
The previous prime is 5051331012509. The next prime is 5051331012557. The reversal of 5051331012541 is 1452101331505.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5051331012541 - 25 = 5051331012509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5051331013541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229605955105 + ... + 229605955126.
It is an arithmetic number, because the mean of its divisors is an integer number (1377635730696).
Almost surely, 25051331012541 is an apocalyptic number.
It is an amenable number.
5051331012541 is a deficient number, since it is larger than the sum of its proper divisors (459211910243).
5051331012541 is a wasteful number, since it uses less digits than its factorization.
5051331012541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 459211910242.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 5051331012541 in words is "five trillion, fifty-one billion, three hundred thirty-one million, twelve thousand, five hundred forty-one".
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