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505212114503 = 796395090057
BaseRepresentation
bin1110101101000001111…
…11010001011001000111
31210022001002201120012102
413112200333101121013
531234133300131003
61024031412542315
751333425055425
oct7264077213107
91708032646172
10505212114503
11185294082248
1281ab662199b
1338844c15ab5
141a64953c115
15d21d4d8588
hex75a0fd1647

505212114503 has 4 divisors (see below), whose sum is σ = 511607204640. Its totient is φ = 498817024368.

The previous prime is 505212114499. The next prime is 505212114523. The reversal of 505212114503 is 305411212505.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 505212114503 - 22 = 505212114499 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (505212114523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3197544950 + ... + 3197545107.

It is an arithmetic number, because the mean of its divisors is an integer number (127901801160).

Almost surely, 2505212114503 is an apocalyptic number.

505212114503 is a deficient number, since it is larger than the sum of its proper divisors (6395090137).

505212114503 is an equidigital number, since it uses as much as digits as its factorization.

505212114503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6395090136.

The product of its (nonzero) digits is 6000, while the sum is 29.

The spelling of 505212114503 in words is "five hundred five billion, two hundred twelve million, one hundred fourteen thousand, five hundred three".

Divisors: 1 79 6395090057 505212114503