Base | Representation |
---|---|
bin | 101111000011110100… |
… | …011011111010111111 |
3 | 11211102112000002001221 |
4 | 233003310123322333 |
5 | 1311441131140411 |
6 | 35114012014211 |
7 | 3436115300515 |
oct | 570364337277 |
9 | 154375002057 |
10 | 50529943231 |
11 | 1a47a921269 |
12 | 9962461367 |
13 | 49c37a9cc1 |
14 | 2634c7c4b5 |
15 | 14ab175071 |
hex | bc3d1bebf |
50529943231 has 4 divisors (see below), whose sum is σ = 50536332000. Its totient is φ = 50523554464.
The previous prime is 50529943187. The next prime is 50529943271. The reversal of 50529943231 is 13234992505.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50529943231 - 29 = 50529942719 is a prime.
It is a super-2 number, since 2×505299432312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50529943271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3182506 + ... + 3198343.
It is an arithmetic number, because the mean of its divisors is an integer number (12634083000).
Almost surely, 250529943231 is an apocalyptic number.
50529943231 is a deficient number, since it is larger than the sum of its proper divisors (6388769).
50529943231 is an equidigital number, since it uses as much as digits as its factorization.
50529943231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6388768.
The product of its (nonzero) digits is 291600, while the sum is 43.
The spelling of 50529943231 in words is "fifty billion, five hundred twenty-nine million, nine hundred forty-three thousand, two hundred thirty-one".
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