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50612434141 = 443114249287
BaseRepresentation
bin101111001000101111…
…000111010011011101
311211122021020001022211
4233020233013103131
51312123240343031
635130120040421
73441136410013
oct571057072335
9154567201284
1050612434141
111a512443975
129986003111
134a079000a9
142641bd28b3
1514b351bbb1
hexbc8bc74dd

50612434141 has 4 divisors (see below), whose sum is σ = 50726683872. Its totient is φ = 50498184412.

The previous prime is 50612434079. The next prime is 50612434183. The reversal of 50612434141 is 14143421605.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50612434141 - 29 = 50612433629 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50612434541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57124201 + ... + 57125086.

It is an arithmetic number, because the mean of its divisors is an integer number (12681670968).

Almost surely, 250612434141 is an apocalyptic number.

It is an amenable number.

50612434141 is a deficient number, since it is larger than the sum of its proper divisors (114249731).

50612434141 is a wasteful number, since it uses less digits than its factorization.

50612434141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114249730.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 50612434141 its reverse (14143421605), we get a palindrome (64755855746).

The spelling of 50612434141 in words is "fifty billion, six hundred twelve million, four hundred thirty-four thousand, one hundred forty-one".

Divisors: 1 443 114249287 50612434141