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5064143303 = 5160798129
BaseRepresentation
bin1001011011101100…
…01011000111000111
3111001221002010122002
410231312023013013
540332410041203
62154302055515
7236331336122
oct45566130707
914057063562
105064143303
1121696388aa
12b93b7a59b
136292296cb
143607db3b9
151e98c6d88
hex12dd8b1c7

5064143303 has 4 divisors (see below), whose sum is σ = 5064293040. Its totient is φ = 5063993568.

The previous prime is 5064143281. The next prime is 5064143317. The reversal of 5064143303 is 3033414605.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 5064143303 - 232 = 769176007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5064143603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2543 + ... + 100671.

It is an arithmetic number, because the mean of its divisors is an integer number (1266073260).

Almost surely, 25064143303 is an apocalyptic number.

5064143303 is a deficient number, since it is larger than the sum of its proper divisors (149737).

5064143303 is an equidigital number, since it uses as much as digits as its factorization.

5064143303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149736.

The product of its (nonzero) digits is 12960, while the sum is 29.

The square root of 5064143303 is about 71162.7943731835. The cubic root of 5064143303 is about 1717.2571326050.

Adding to 5064143303 its reverse (3033414605), we get a palindrome (8097557908).

The spelling of 5064143303 in words is "five billion, sixty-four million, one hundred forty-three thousand, three hundred three".

Divisors: 1 51607 98129 5064143303