Base | Representation |
---|---|
bin | 100101000011100010010… |
… | …1010001110100110111111 |
3 | 200000212111110202210000222 |
4 | 1022013010222032212333 |
5 | 1131420111411244413 |
6 | 14455341050411555 |
7 | 1033642133523614 |
oct | 112070452164677 |
9 | 20025443683028 |
10 | 5092835649983 |
11 | 169394aa55434 |
12 | 6a3038430bbb |
13 | 2ac338516333 |
14 | 1386cd10850b |
15 | 8c7229cab08 |
hex | 4a1c4a8e9bf |
5092835649983 has 4 divisors (see below), whose sum is σ = 5093398963488. Its totient is φ = 5092272336480.
The previous prime is 5092835649971. The next prime is 5092835650051. The reversal of 5092835649983 is 3899465382905.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5092835649983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5092835699983) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281643191 + ... + 281661272.
It is an arithmetic number, because the mean of its divisors is an integer number (1273349740872).
Almost surely, 25092835649983 is an apocalyptic number.
5092835649983 is a deficient number, since it is larger than the sum of its proper divisors (563313505).
5092835649983 is an equidigital number, since it uses as much as digits as its factorization.
5092835649983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 563313504.
The product of its (nonzero) digits is 503884800, while the sum is 71.
The spelling of 5092835649983 in words is "five trillion, ninety-two billion, eight hundred thirty-five million, six hundred forty-nine thousand, nine hundred eighty-three".
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