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5100000055 = 51020000011
BaseRepresentation
bin1001011111111101…
…11101001100110111
3111011102112211211221
410233332331030313
540421100000210
62202022411211
7240245166553
oct45776751467
914142484757
105100000055
1121878a9587
12ba3b90b07
136337a2417
14365492863
151ecb0b1da
hex12ffbd337

5100000055 has 4 divisors (see below), whose sum is σ = 6120000072. Its totient is φ = 4080000040.

The previous prime is 5100000053. The next prime is 5100000071. The reversal of 5100000055 is 5500000015.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5100000055 - 21 = 5100000053 is a prime.

It is a super-2 number, since 2×51000000552 = 52020001122000006050, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5099999984 and 5100000038.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5100000053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 510000001 + ... + 510000010.

It is an arithmetic number, because the mean of its divisors is an integer number (1530000018).

Almost surely, 25100000055 is an apocalyptic number.

5100000055 is a deficient number, since it is larger than the sum of its proper divisors (1020000017).

5100000055 is a wasteful number, since it uses less digits than its factorization.

5100000055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1020000016.

The product of its (nonzero) digits is 125, while the sum is 16.

The square root of 5100000055 is about 71414.2846705055. The cubic root of 5100000055 is about 1721.3006269140.

The spelling of 5100000055 in words is "five billion, one hundred million, fifty-five", and thus it is an aban number.

Divisors: 1 5 1020000011 5100000055