Base | Representation |
---|---|
bin | 101111011111111010… |
… | …100101001110011101 |
3 | 11212122100222022022000 |
4 | 233133322211032131 |
5 | 1313422314110003 |
6 | 35232451112513 |
7 | 3453601015056 |
oct | 573772451635 |
9 | 155570868260 |
10 | 51001316253 |
11 | 1a6a1a05848 |
12 | 9a742a2739 |
13 | 4a6a34b054 |
14 | 267b70172d |
15 | 14d77361a3 |
hex | bdfea539d |
51001316253 has 16 divisors (see below), whose sum is σ = 75666878400. Its totient is φ = 33951659760.
The previous prime is 51001316231. The next prime is 51001316273. The reversal of 51001316253 is 35261310015.
51001316253 is a `hidden beast` number, since 5 + 1 + 0 + 0 + 1 + 31 + 625 + 3 = 666.
It is not a de Polignac number, because 51001316253 - 28 = 51001315997 is a prime.
It is a super-2 number, since 2×510013162532 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51001316273) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1348158 + ... + 1385471.
It is an arithmetic number, because the mean of its divisors is an integer number (4729179900).
Almost surely, 251001316253 is an apocalyptic number.
It is an amenable number.
51001316253 is a deficient number, since it is larger than the sum of its proper divisors (24665562147).
51001316253 is a wasteful number, since it uses less digits than its factorization.
51001316253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2734329 (or 2734323 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 27.
Adding to 51001316253 its reverse (35261310015), we get a palindrome (86262626268).
The spelling of 51001316253 in words is "fifty-one billion, one million, three hundred sixteen thousand, two hundred fifty-three".
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