Base | Representation |
---|---|
bin | 101111011111111011… |
… | …011100100111011101 |
3 | 11212122101101211111222 |
4 | 233133323130213131 |
5 | 1313422343340013 |
6 | 35232500023125 |
7 | 3453602651402 |
oct | 573773344735 |
9 | 155571354458 |
10 | 51001543133 |
11 | 1a6a2050252 |
12 | 9a74391aa5 |
13 | 4a6a3ca3b8 |
14 | 267b7602a9 |
15 | 14d777d508 |
hex | bdfedc9dd |
51001543133 has 4 divisors (see below), whose sum is σ = 51002576988. Its totient is φ = 51000509280.
The previous prime is 51001543067. The next prime is 51001543163. The reversal of 51001543133 is 33134510015.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33134510015 = 5 ⋅6626902003.
It can be written as a sum of positive squares in 2 ways, for example, as 25560655129 + 25440888004 = 159877^2 + 159502^2 .
It is a cyclic number.
It is not a de Polignac number, because 51001543133 - 232 = 46706575837 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51001543163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 439016 + ... + 542897.
It is an arithmetic number, because the mean of its divisors is an integer number (12750644247).
Almost surely, 251001543133 is an apocalyptic number.
It is an amenable number.
51001543133 is a deficient number, since it is larger than the sum of its proper divisors (1033855).
51001543133 is an equidigital number, since it uses as much as digits as its factorization.
51001543133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1033854.
The product of its (nonzero) digits is 2700, while the sum is 26.
The spelling of 51001543133 in words is "fifty-one billion, one million, five hundred forty-three thousand, one hundred thirty-three".
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