Base | Representation |
---|---|
bin | 101111100000000001… |
… | …001010001000101101 |
3 | 11212122111012220020122 |
4 | 233200001022020231 |
5 | 1313423234242201 |
6 | 35232552054325 |
7 | 3453621455333 |
oct | 574001121055 |
9 | 155574186218 |
10 | 51003040301 |
11 | 1a6a2983084 |
12 | 9a749943a5 |
13 | 4a6a8029b5 |
14 | 267ba2db53 |
15 | 14d7976e1b |
hex | be004a22d |
51003040301 has 4 divisors (see below), whose sum is σ = 51005601504. Its totient is φ = 51000479100.
The previous prime is 51003040289. The next prime is 51003040321. The reversal of 51003040301 is 10304030015.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51003040301 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51003040301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51003040321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1250495 + ... + 1290636.
It is an arithmetic number, because the mean of its divisors is an integer number (12751400376).
Almost surely, 251003040301 is an apocalyptic number.
It is an amenable number.
51003040301 is a deficient number, since it is larger than the sum of its proper divisors (2561203).
51003040301 is a wasteful number, since it uses less digits than its factorization.
51003040301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2561202.
The product of its (nonzero) digits is 180, while the sum is 17.
Adding to 51003040301 its reverse (10304030015), we get a palindrome (61307070316).
The spelling of 51003040301 in words is "fifty-one billion, three million, forty thousand, three hundred one".
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