Base | Representation |
---|---|
bin | 100101000111010101101… |
… | …0011100001001111001011 |
3 | 200001122120110210221201102 |
4 | 1022032223103201033023 |
5 | 1132033322022414123 |
6 | 14503211145212015 |
7 | 1034351353210046 |
oct | 112165323411713 |
9 | 20048513727642 |
10 | 5101000201163 |
11 | 169735a6a3599 |
12 | 6a473679100b |
13 | 2b0039b815c9 |
14 | 138c655a7c5d |
15 | 8ca4e67c028 |
hex | 4a3ab4e13cb |
5101000201163 has 4 divisors (see below), whose sum is σ = 5102025945168. Its totient is φ = 5099974457160.
The previous prime is 5101000201159. The next prime is 5101000201201. The reversal of 5101000201163 is 3611020001015.
5101000201163 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5101000201163 - 22 = 5101000201159 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5101000201153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512864543 + ... + 512874488.
It is an arithmetic number, because the mean of its divisors is an integer number (1275506486292).
Almost surely, 25101000201163 is an apocalyptic number.
5101000201163 is a deficient number, since it is larger than the sum of its proper divisors (1025744005).
5101000201163 is a wasteful number, since it uses less digits than its factorization.
5101000201163 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1025744004.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 5101000201163 its reverse (3611020001015), we get a palindrome (8712020202178).
The spelling of 5101000201163 in words is "five trillion, one hundred one billion, two hundred one thousand, one hundred sixty-three".
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