Base | Representation |
---|---|
bin | 10111001100101000101101… |
… | …00110010011110100100111 |
3 | 20200121200010110221200020012 |
4 | 23212110112212103310213 |
5 | 23141233433130403012 |
6 | 300254242030000435 |
7 | 13513321423212101 |
oct | 1346242646236447 |
9 | 220550113850205 |
10 | 51011705716007 |
11 | 15287a41005743 |
12 | 587a4b104611b |
13 | 22604c9ba719a |
14 | c84da0546571 |
15 | 5d6de8db6622 |
hex | 2e6516993d27 |
51011705716007 has 4 divisors (see below), whose sum is σ = 51013674317760. Its totient is φ = 51009737114256.
The previous prime is 51011705716001. The next prime is 51011705716021. The reversal of 51011705716007 is 70061750711015.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51011705716007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51011705716001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 984262007 + ... + 984313832.
It is an arithmetic number, because the mean of its divisors is an integer number (12753418579440).
Almost surely, 251011705716007 is an apocalyptic number.
51011705716007 is a deficient number, since it is larger than the sum of its proper divisors (1968601753).
51011705716007 is a wasteful number, since it uses less digits than its factorization.
51011705716007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1968601752.
The product of its (nonzero) digits is 51450, while the sum is 41.
The spelling of 51011705716007 in words is "fifty-one trillion, eleven billion, seven hundred five million, seven hundred sixteen thousand, seven".
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