Base | Representation |
---|---|
bin | 100101000111100100111… |
… | …1001101001010101111011 |
3 | 200001200220020200212020120 |
4 | 1022033021321221111323 |
5 | 1132040344424343230 |
6 | 14503334123224323 |
7 | 1034400155244033 |
oct | 112171171512573 |
9 | 20050806625216 |
10 | 5101513512315 |
11 | 16975a3421890 |
12 | 6a485a6780a3 |
13 | 2b00bc31740c |
14 | 138cb38268c3 |
15 | 8ca7e774310 |
hex | 4a3c9e6957b |
5101513512315 has 32 divisors (see below), whose sum is σ = 8905005893376. Its totient is φ = 2473309445760.
The previous prime is 5101513512313. The next prime is 5101513512377. The reversal of 5101513512315 is 5132153151015.
It is not a de Polignac number, because 5101513512315 - 21 = 5101513512313 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (5101513512313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1775152 + ... + 3654338.
It is an arithmetic number, because the mean of its divisors is an integer number (278281434168).
Almost surely, 25101513512315 is an apocalyptic number.
5101513512315 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5101513512315 is a deficient number, since it is larger than the sum of its proper divisors (3803492381061).
5101513512315 is a wasteful number, since it uses less digits than its factorization.
5101513512315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1895659.
The product of its (nonzero) digits is 11250, while the sum is 33.
The spelling of 5101513512315 in words is "five trillion, one hundred one billion, five hundred thirteen million, five hundred twelve thousand, three hundred fifteen".
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