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5102113 = 23221831
BaseRepresentation
bin10011011101101000100001
3100121012210011
4103131220201
52301231423
6301204521
761236652
oct23355041
910535704
105102113
112975325
121860741
131098403
1496b529
156abb0d
hex4dda21

5102113 has 4 divisors (see below), whose sum is σ = 5323968. Its totient is φ = 4880260.

The previous prime is 5102107. The next prime is 5102129. The reversal of 5102113 is 3112015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5102113 - 221 = 3004961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5102093 and 5102102.

It is not an unprimeable number, because it can be changed into a prime (5106113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110893 + ... + 110938.

It is an arithmetic number, because the mean of its divisors is an integer number (1330992).

Almost surely, 25102113 is an apocalyptic number.

It is an amenable number.

5102113 is a deficient number, since it is larger than the sum of its proper divisors (221855).

5102113 is a wasteful number, since it uses less digits than its factorization.

5102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221854.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 5102113 is about 2258.7857357439. The cubic root of 5102113 is about 172.1538307395.

Adding to 5102113 its reverse (3112015), we get a palindrome (8214128).

The spelling of 5102113 in words is "five million, one hundred two thousand, one hundred thirteen".

Divisors: 1 23 221831 5102113