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51025230131 = 597910947271
BaseRepresentation
bin101111100001010101…
…110011100100110011
311212201000222020222012
4233201111303210303
51313444424331011
635235103433135
73454311204611
oct574125634463
9155630866865
1051025230131
111a704459687
129a802b57ab
134a722a1a85
1426809686b1
1514d98aba8b
hexbe1573933

51025230131 has 8 divisors (see below), whose sum is σ = 52546905600. Its totient is φ = 49525449480.

The previous prime is 51025230127. The next prime is 51025230143. The reversal of 51025230131 is 13103252015.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51025230131 - 22 = 51025230127 is a prime.

It is a super-2 number, since 2×510252301312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51025230097 and 51025230106.

It is not an unprimeable number, because it can be changed into a prime (51025230331) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5468975 + ... + 5478296.

It is an arithmetic number, because the mean of its divisors is an integer number (6568363200).

Almost surely, 251025230131 is an apocalyptic number.

51025230131 is a deficient number, since it is larger than the sum of its proper divisors (1521675469).

51025230131 is a wasteful number, since it uses less digits than its factorization.

51025230131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10947409.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 51025230131 its reverse (13103252015), we get a palindrome (64128482146).

The spelling of 51025230131 in words is "fifty-one billion, twenty-five million, two hundred thirty thousand, one hundred thirty-one".

Divisors: 1 59 79 4661 10947271 645888989 864834409 51025230131