Base | Representation |
---|---|
bin | 101111100010001110… |
… | …101100011110010101 |
3 | 11212202002000220221001 |
4 | 233202032230132111 |
5 | 1314012234041003 |
6 | 35240355223301 |
7 | 3454552026241 |
oct | 574216543625 |
9 | 155662026831 |
10 | 51040143253 |
11 | 1a711915080 |
12 | 9a852a7b31 |
13 | 4a753c39c8 |
14 | 268292b421 |
15 | 14dad5561d |
hex | be23ac795 |
51040143253 has 16 divisors (see below), whose sum is σ = 56609020800. Its totient is φ = 45632248000.
The previous prime is 51040143241. The next prime is 51040143257. The reversal of 51040143253 is 35234104015.
It is a cyclic number.
It is not a de Polignac number, because 51040143253 - 229 = 50503272341 is a prime.
It is a super-3 number, since 3×510401432533 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51040143257) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11376 + ... + 319702.
It is an arithmetic number, because the mean of its divisors is an integer number (3538063800).
Almost surely, 251040143253 is an apocalyptic number.
It is an amenable number.
51040143253 is a deficient number, since it is larger than the sum of its proper divisors (5568877547).
51040143253 is a wasteful number, since it uses less digits than its factorization.
51040143253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 308588.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 51040143253 its reverse (35234104015), we get a palindrome (86274247268).
The spelling of 51040143253 in words is "fifty-one billion, forty million, one hundred forty-three thousand, two hundred fifty-three".
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