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5104330311 = 31701443437
BaseRepresentation
bin1001100000011110…
…11110011001000111
3111011201200211211210
410300033132121013
540423202032221
62202255302503
7240330043323
oct46017363107
914151624753
105104330311
11218a296a03
12ba551aa33
1363465a3c2
14365c9c983
151ed1b4276
hex1303de647

5104330311 has 4 divisors (see below), whose sum is σ = 6805773752. Its totient is φ = 3402886872.

The previous prime is 5104330303. The next prime is 5104330313. The reversal of 5104330311 is 1130334015.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5104330311 - 23 = 5104330303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5104330313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850721716 + ... + 850721721.

It is an arithmetic number, because the mean of its divisors is an integer number (1701443438).

Almost surely, 25104330311 is an apocalyptic number.

5104330311 is a deficient number, since it is larger than the sum of its proper divisors (1701443441).

5104330311 is a wasteful number, since it uses less digits than its factorization.

5104330311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1701443440.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 5104330311 is about 71444.5960937565. The cubic root of 5104330311 is about 1721.7876572224.

Adding to 5104330311 its reverse (1130334015), we get a palindrome (6234664326).

The spelling of 5104330311 in words is "five billion, one hundred four million, three hundred thirty thousand, three hundred eleven".

Divisors: 1 3 1701443437 5104330311