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51046313403 = 317015437801
BaseRepresentation
bin101111100010100110…
…001110110110111011
311212202111122101210010
4233202212032312323
51314020324012103
635241135353003
73454655335101
oct574246166673
9155674571703
1051046313403
111a715349878
129a87382763
134a76774297
142683695c71
1514db673903
hexbe298edbb

51046313403 has 4 divisors (see below), whose sum is σ = 68061751208. Its totient is φ = 34030875600.

The previous prime is 51046313399. The next prime is 51046313419. The reversal of 51046313403 is 30431364015.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 51046313403 - 22 = 51046313399 is a prime.

It is a super-2 number, since 2×510463134032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51046313453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8507718898 + ... + 8507718903.

It is an arithmetic number, because the mean of its divisors is an integer number (17015437802).

Almost surely, 251046313403 is an apocalyptic number.

51046313403 is a deficient number, since it is larger than the sum of its proper divisors (17015437805).

51046313403 is a wasteful number, since it uses less digits than its factorization.

51046313403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17015437804.

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 51046313403 its reverse (30431364015), we get a palindrome (81477677418).

The spelling of 51046313403 in words is "fifty-one billion, forty-six million, three hundred thirteen thousand, four hundred three".

Divisors: 1 3 17015437801 51046313403