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5105035402013 = 6776194558239
BaseRepresentation
bin100101001001001101111…
…0100100101101100011101
3200002000222200202101122202
41022102123310211230131
51132120103030331023
614505115413421245
71034553351643031
oct112223364455435
920060880671582
105105035402013
11169904043a728
126a548203a825
132b0530b79311
141391294821c1
158cbd8a57128
hex4a49bd25b1d

5105035402013 has 4 divisors (see below), whose sum is σ = 5181229960320. Its totient is φ = 5028840843708.

The previous prime is 5105035402007. The next prime is 5105035402069. The reversal of 5105035402013 is 3102045305015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5105035402013 - 216 = 5105035336477 is a prime.

It is a super-2 number, since 2×51050354020132 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5105035402003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38097279053 + ... + 38097279186.

It is an arithmetic number, because the mean of its divisors is an integer number (1295307490080).

Almost surely, 25105035402013 is an apocalyptic number.

It is an amenable number.

5105035402013 is a deficient number, since it is larger than the sum of its proper divisors (76194558307).

5105035402013 is an equidigital number, since it uses as much as digits as its factorization.

5105035402013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76194558306.

The product of its (nonzero) digits is 9000, while the sum is 29.

The spelling of 5105035402013 in words is "five trillion, one hundred five billion, thirty-five million, four hundred two thousand, thirteen".

Divisors: 1 67 76194558239 5105035402013