Base | Representation |
---|---|
bin | 101111100011000000… |
… | …100111011111100011 |
3 | 11212202222122210122021 |
4 | 233203000213133203 |
5 | 1314024111330201 |
6 | 35241543522311 |
7 | 3455101203205 |
oct | 574300473743 |
9 | 155688583567 |
10 | 51053230051 |
11 | 1a71924340a |
12 | 9a89759397 |
13 | 4a78026585 |
14 | 2684576775 |
15 | 14dc08cea1 |
hex | be30277e3 |
51053230051 has 4 divisors (see below), whose sum is σ = 51053877952. Its totient is φ = 51052582152.
The previous prime is 51053230049. The next prime is 51053230069. The reversal of 51053230051 is 15003235015.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51053230051 - 21 = 51053230049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 51053229998 and 51053230025.
It is not an unprimeable number, because it can be changed into a prime (51053230651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186240 + ... + 369853.
It is an arithmetic number, because the mean of its divisors is an integer number (12763469488).
Almost surely, 251053230051 is an apocalyptic number.
51053230051 is a deficient number, since it is larger than the sum of its proper divisors (647901).
51053230051 is an equidigital number, since it uses as much as digits as its factorization.
51053230051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 647900.
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 51053230051 its reverse (15003235015), we get a palindrome (66056465066).
The spelling of 51053230051 in words is "fifty-one billion, fifty-three million, two hundred thirty thousand, fifty-one".
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