Base | Representation |
---|---|
bin | 100101001001011010010… |
… | …0011011101101110100111 |
3 | 200002002001121112121010212 |
4 | 1022102310203131232213 |
5 | 1132121430241441320 |
6 | 14505224515210035 |
7 | 1034566550614346 |
oct | 112226443355647 |
9 | 20062047477125 |
10 | 5105450343335 |
11 | 1699233690241 |
12 | 6a5578ba691b |
13 | 2b0598b1c624 |
14 | 139168615b5d |
15 | 8cc101bc9c5 |
hex | 4a4b48ddba7 |
5105450343335 has 8 divisors (see below), whose sum is σ = 6130627506000. Its totient is φ = 4081635545344.
The previous prime is 5105450343317. The next prime is 5105450343377. The reversal of 5105450343335 is 5333430545015.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5105450343335 - 212 = 5105450339239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5105450343292 and 5105450343301.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 340582922 + ... + 340597911.
It is an arithmetic number, because the mean of its divisors is an integer number (766328438250).
Almost surely, 25105450343335 is an apocalyptic number.
5105450343335 is a deficient number, since it is larger than the sum of its proper divisors (1025177162665).
5105450343335 is a wasteful number, since it uses less digits than its factorization.
5105450343335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 681182337.
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 5105450343335 in words is "five trillion, one hundred five billion, four hundred fifty million, three hundred forty-three thousand, three hundred thirty-five".
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