Base | Representation |
---|---|
bin | 101111100011001000… |
… | …111001101000101001 |
3 | 11212210010202010022210 |
4 | 233203020321220221 |
5 | 1314030140322023 |
6 | 35242102235333 |
7 | 3455125516044 |
oct | 574310715051 |
9 | 155703663283 |
10 | 51055401513 |
11 | 1a71a496906 |
12 | 9a8a425b49 |
13 | 4a78606a6c |
14 | 268497dc5b |
15 | 14dc36b593 |
hex | be3239a29 |
51055401513 has 4 divisors (see below), whose sum is σ = 68073868688. Its totient is φ = 34036934340.
The previous prime is 51055401503. The next prime is 51055401557. The reversal of 51055401513 is 31510455015.
51055401513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 51055401513 - 225 = 51021847081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51055401503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8509233583 + ... + 8509233588.
It is an arithmetic number, because the mean of its divisors is an integer number (17018467172).
Almost surely, 251055401513 is an apocalyptic number.
It is an amenable number.
51055401513 is a deficient number, since it is larger than the sum of its proper divisors (17018467175).
51055401513 is a wasteful number, since it uses less digits than its factorization.
51055401513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17018467174.
The product of its (nonzero) digits is 7500, while the sum is 30.
Adding to 51055401513 its reverse (31510455015), we get a palindrome (82565856528).
The spelling of 51055401513 in words is "fifty-one billion, fifty-five million, four hundred one thousand, five hundred thirteen".
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