Base | Representation |
---|---|
bin | 101111100101110100… |
… | …001100001010011111 |
3 | 11212220021020102000000 |
4 | 233211310030022133 |
5 | 1314123134212111 |
6 | 35250344505343 |
7 | 3456212263140 |
oct | 574564141237 |
9 | 155807212000 |
10 | 51100304031 |
11 | 1a742875827 |
12 | 9aa147b253 |
13 | 4a849c8bba |
14 | 268a90bac7 |
15 | 14e128ac56 |
hex | be5d0c29f |
51100304031 has 28 divisors (see below), whose sum is σ = 87560474832. Its totient is φ = 29200170816.
The previous prime is 51100304023. The next prime is 51100304033. The reversal of 51100304031 is 13040300115.
It is not a de Polignac number, because 51100304031 - 23 = 51100304023 is a prime.
It is a super-2 number, since 2×511003040312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51100303995 and 51100304013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51100304033) by changing a digit.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 5001786 + ... + 5011991.
Almost surely, 251100304031 is an apocalyptic number.
51100304031 is a deficient number, since it is larger than the sum of its proper divisors (36460170801).
51100304031 is an equidigital number, since it uses as much as digits as its factorization.
51100304031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10013802 (or 10013787 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 18.
Adding to 51100304031 its reverse (13040300115), we get a palindrome (64140604146).
The spelling of 51100304031 in words is "fifty-one billion, one hundred million, three hundred four thousand, thirty-one".
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